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Friday 27 March 2015

LP alignment - Sunel (Maths dept.)

Teacher: Mr. Mukesh                       Grade: VII

TOPIC = AREA OF A CIRCLE.
Aim – use the formula to find the area of a circle .

Resources = circular cut –out of 4 cm radius, chart , scale,
 etc.
Learning outcomes =  students will be able to deduce and use the formula to find the area of a circle.

Teacher´s  action

Student´s response

What is pi?


What is the area of a rectangle?


What is the circumference of a circle?

What is the area of a circle?

To day we will deduce the formula to find the area of a circle

Students were divided into pairs. And were given circle cut out to each pair.

Questions: What did you do? Which shape did you get after arranging the pieces?

We then arranged them to get a parallelogram.
What is the area of a   parallelogram?

Discussion = Are the areas of the parallelogram and circle the same? Why?

The circumference of the circle was divided into 2 parts by  colouring the sectors in two different colour. We now the area of a parallelogram =base ×height =π r ×r =




What about the perimeter of the semicircle

 Discussion  
The area of a semicircle is half of the area of the circle.
 The perimeter of a semi circle is never half of the circumference of the circle because in perimeter we also measure the length of the diameter as it becomes the outer edge of the semicircle.

Pi is a constant for all circles and its value is 22/7 or 3.14.


base × height



C =2πr

No ,answer

Listening


Student responses on the board .





Base × height


 No answer
                           Area of circle = area of parallelogram
                           Area of circle = base× height
                          Area  of circle = πr × r
                                                   = πr²

Student asks some Question.

     


Assessment = 1. Find the area and perimeter of the circle radius 6.5?
                       2. Find the area and perimeter of the semicircle
                            


                         3. Find the area of the circle .if the d=35cm of a circle.

Black board work =

 Area of circle = π r²
Area of semicircle =Area of Inner circle -- Area of outer circle 
Circumference of circle = 2πr

Report lesson plan =

                                   My lesson plan and activity are aligned with learning outcome and it helped students in deep understanding. Now student are thorough with the concept and are able to find the area between concentric circles using the area of a circle.




1 comment:

Reniscience Education said...

Thanks for posting this. Here is some feedback to think about:
1. In writing your lesson plan, you need to be a bit more specific when it comes to giving instructions for tasks. For example, you mention "Students were divided into pairs. And were given circle cut out to each pair." However it is not clear WHAT THEY ARE SUPPOSED TO DO...after this you directly go to the questions where you ask them "What did you do?" but I would like to know what instructions were they given - what the PROBLEM or task given to them was. This is not clear and this is actually the crux of your lesson.

2. How many different student responses did you get? 5, 6...? did all students complete the task or did some of them not do it ?

3. In your discussion, you talk about the area of a semi circle but that is not your LO. Neither is perimeter in your LO. SO why did you discuss these?

4. Since your LO is about DEDUCING the formula, I would like to know did the children REALLY deduce the formula themselves or did YOU explain it to them after the activity was done?

5. Please reflect again if the three are actually aligned or not :)